Question

x4-(y+z) 4 factories​

Answer 1

 

$x^4-(y+z)^4 \\ \\ (x^2+(y+z)^2)(x^2-(y+z)^2) \ \ \ \ \ [a^2-b^2=(a+b)(a-b)] \\ \\ (x^2+y^2+z^2+2yz)(x+y+z)(x-(y+z)) \\ \\ (x^2+y^2+z^2+2yz)(x+y+z)(x-y-z)$

$\therefore\ x^4-(y+z)^4=(x^2+y^2+z^2+2yz)(x+y+z)(x-y-z)$