x⁴-(y+z)⁴ factorise it
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Answered by
62
Step-by-step explanation:
In this question, we only use the identity [a² - b² = (a + b)(a - b)]
x⁴ - (y+z)⁴
= (x²)² - {(y+z)²}²
= {x² + (y+z)²}{x² - (y+z)²}
= {x² + y² + z² + 2yz}{x + (y+z)}{x - (y+z)}
= (x² + y² + z² + 2yz)(x + y + z)(x - y - z)
Answered by
30
In this question, we only use the identity [a² - b² = (a + b)(a - b)]
x⁴ - (y+z)⁴
= (x²)² - {(y+z)²}²
= {x² + (y+z)²}{x² - (y+z)²}
= {x² + y² + z² + 2yz}{x + (y+z)}{x - (y+z)}
= (x² + y² + z² + 2yz)(x + y + z)(x - y - z)
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