Math, asked by genius1072, 1 year ago

x4y2 - 10x²y + 25 factorize​

Answers

Answered by Shahoodalam
2

Hello Friend.

Here is your answer below,,

x {}^{4} y {}^{2}  - 10x {}^{2} y + 25 = 0 \\  = x {}^{4} y {}^{2}  - 5x {}^{2} y - 5x {}^{2} y + 25 = 0 \\  =  > x {}^{2} y(x {}^{2} y - 5) - 5(x {}^{2} y - 5) = 0 \\  =  > (x {}^{2} y - 5)(x {}^{2} y - 5) = 0 \\  =  > x {}^{2} y - 5 = 0 \\   =  > x {}^{2} y = 5 \\  =  > x {}^{2}  =  \frac{5}{y}  \\  =  > x =  \sqrt{ \frac{5}{y} }  \\  =  > same \: as \\  =  > x =  \sqrt{ \frac{5}{y} }

I hope that helps you

Answered by Golutayal5
0

Answer: x^4 y^2 - 10 x^2 y + 25

(x^2)^2 + (5)^2 -2 × (x^2 y) × (5)

(x^2 y - 5)^2

(x^2 y - 5) (x^2 y - 5)

So, the factors are (x^2 y - 5) and (x^2 y - 5)

Hope it will help you

Step-by-step explanation:

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