Question

x6 -1 factorise and give the ans​

Answer 1

Answer:

Factorise

Step-by-step explanation:

     $x^{6} - 1$

= $(x^{3})^{2} - 1^{2}$

= $(x^{3} - 1) (x^{3} + 1) ( using* identity (a+b)(a-b) = a^{2} -b^{2}$

= $[(x - 1) (x^{2} + x +1)] [(x + 1) (x^{2} - x +1)]$