Question

(xa+b)3 .(xb+c)3 .(xc+a)3 ÷(xa . xb . xc)6​

Answer 1

Step-by-step explanation:

(x−a)3+(x−b)3+(x−c)3−3(x−a)(x−b)(x−c)   and a+b+c=3x

We know that a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−ac−bc)

If (a+b+c)=0, then.a3+b3+c3=3abc

Here,a=x−a

b=x−b

c=x−c and a+b+c=x−a+x−b+x−c=3x−(a+b+c)=3x−3x=0

Thus,(x−a)3+(x−b)3+(x−c)3−3(x−a)(x−b)(x−c)

=0

Answer 2

Answer:

Step-by-step explanation: