Question

(xa+d)2 (xb+c)2 (xc+a)2%(xa xb xc)3

Answer 1

Step-by-step explanation:

Answer ANSWER ANSWER ANSWER

Answer 2

Answer:

Step-by-step explanation:

Given that,

=(xa+d)2 (xb+c)2 (xc+a)2% (xa xb xc)3

=(2xa+2d) (2xb+2c) (2xc+2a)/100

(3xaxbxc)

'Multiply first two terms and next two terms'

=(4xaxb+4xbd+4xac+4cd) (6xaxbxcxc+6xaxbxca)/100

'Now multiply above two terms'

=(24xaxbxcxcxaxb+24xaxbxcxcxbd+24xaxbxcxcxac+24xaxbxcxccd+24xaxbxacxaxb+24xaxbxacxbd+24xaxbxacxac+24xaxbxaccd)/100

'Now take 24 as common'

=24[(xa)^2 (xb)^2 (xc)^2 + (xc)^2 (xa)(xb)(xbd) + (xc)^2 (xa)(xb) (xad) + (xc)^2 (xa)(xb)(cd) + (xa)^2 (xb)^2 (xac) + (xa)(xb)(xac)(xbd) + (xa)(xb)(xac)^2 + (xa)(xb)(xac)(cd)]/100

I'm sorry this might not be the correct answer