Question

xample (14)
If speed increases by 33.33%, what is the percent
reduction in time taken to travel the same distance?​

Answer 1

Answer:

≈25%

Step-by-step explanation:

distance= speed*time

If speed increases by 33.33%, new speed will be s*1.33

then time will be reduced 1/1.33≈0.75 times or by 25%

Answer 2

Answer:

The percent reduction in time taken to travel the same distance is 25%.

Step-by-step explanation:

• Speed (v) = distance (s)/time (t).
• Here speed and time are inversely proportionate. So if speed is increased then time will decrease.
• Initial: Suppose at 1st speed was 100 unit

                     Distance covered = s, time = distance/speed = s/100

• Final: Now speed = 100 + 33.33 = 133.33 unit.
•           Distance covered = s, time = distance/speed = s/133.33
• Change: Change in speed = $\frac{s}{100}$ - $\frac{s}{133.33}$ = 0.0025s unit
• Percent reduction in speed = $\frac{change in speed}{initial speed}$ × 100%

                                                       = $\frac{0.0025s}{s/100}$ × 100%

                                                       = 0.25 × 100%

                                                       = 25%

∴Speed is reduced by 25%.