Question

xan anyone alive first five I'll mark yours a brainilist ​

Answer 1

Answer:

don't know.......

sorry

Answer 2

Answer:1st one is not visible.

2)cosA=adjacent/hypotenuse

3)tanΦ=√3=opp/adj

Apply pythagoras theorem,

Hy²=s²+s²

Hy²=3+1

Hy=2

Now,value of 1+cosΦ=1+π/3=3+π/3

5)sinA=1/√2,cotB=1

Apply pythagoras theorem to both of them,we get on solving is

CosA=1/√2,cosB=1/√2,sinB=1/√2

Now,sin(A+B)=sinAcosB+cosAsinB

1/√2×1/√2+1/√2×1/√2=1/2+1/2

=1+1/2=2/2=1

Hence, LHS=RHS

So proved.

Step-by-step explanation:

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