Question

xc3h8+x02=zco2+4h2o what are values of xyz
$=$
​

Answer 1

Answer:

If xyz ≠ 0, what is the value of ?

(1) y^2 = x^4

(2) x = 2 and y = 4

Answer 2

SOLUTION

GIVEN

$\sf{xC_3H_8 + yO_2 = zCO_2 + 4H_2O}$

TO DETERMINE

The value of x , y , z

CONCEPT TO BE IMPLEMENTED

In a balanced chemical equation the number of atoms for each element involved in the reaction in the Reactant side and product side are equal

EVALUATION

Here it is given that

$\sf{xC_3H_8 + yO_2 = zCO_2 + 4H_2O}$

Now from above chemical reaction we get

$\sf{Atom \: \: \: \: \: \: \: \: \: Reactant \: Side \: \: \: \: \: \: \: \: \: Product \: Side}$

$\sf{C \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 3x \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: z}$

$\sf{H \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 8x \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 8}$

$\sf{O \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2y \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 2z + 4}$

Comparing both sides of H atom we get

$\sf{8x = 8}$

$\therefore \: \: \: \sf{ x = 1}$

Now Comparing both sides of C atom we get

$\sf{3x = z}$

$\implies \sf{z = 3x}$

$\implies \sf{z = 3 \times 1}$

$\therefore \: \: \sf{z = 3}$

Now Comparing both sides of O atom we get

$\sf{2y = 2z + 4}$

$\implies \sf{2y = (2 \times 3) + 4}$

$\implies \sf{2y = 6 + 4}$

$\implies \sf{2y = 10}$

$\implies \sf{y = 5}$

FINAL ANSWER

Hence the required values are

$\sf{x = 1 \: , y = 5 \:, \: z = 3}$

The balanced chemical equation is

$\sf{C_3H_8 + 5O_2 = 3CO_2 + 4H_2O}$

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