Math, asked by janajaivid6172, 11 months ago

Xcosθ-ysinθ=a, xsinθ+ycosθ=b prove that x2+y2=a2+b2

Answers

Answered by ArjunPartha
2

Answer:

a^2+b^2=x^2cos^tita+y^2sin^tita+x^2sin^2tita+y^2cos^2 tita-2xy sin tita cos tita+2xysin tita cos tita=x^2 + y^2

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