Question

xCosec 30 sec²us/ 8cos²45 Sin²60=tan²60-tan²30?
Find x​

Answer 1

Answer:

xcosec30sec  

2

45sin  

2

60=tan  

2

60−tan  

2

30?

Solve for c

c=  

15sin(120)cos(30)

cos(45)  

−  

eosx

30((sin(30)cos(60))  

2

−(sin(60)cos(30))  

2

)

​

 

​

 

​

 

c=−  

15sin(120)cos(30)

cos(45)  

−  

eosx

30((sin(30)cos(60))  

2

−(sin(60)cos(30))  

2

)

​

 

​

 

​

, (s<0 and o<0 and x<0) or (x<0 and o>0 and s>0) or (o<0 and x>0 and s>0) or (s<0 and x>0 and o>0)

Steps by Finding Square Root

xcosec30sec  

2

45sin  

2

60=tan  

2

60−tan  

2

30?

Multiply c and c to get c  

2

.

30xc  

2

ose(sec(45))  

2

(sin(60))  

2

=(tan(60))  

2

−(tan(30))  

2

 

Divide both sides by 30xose(sec(45))  

2

(sin(60))  

2

.

30e(sin(60))  

2

(sec(45))  

2

osx

30e(sin(60))  

2

(sec(45))  

2

osxc  

2

 

​

=  

30e(sin(60))  

2

(sec(45))  

2

osx

(tan(60))  

2

−(tan(30))  

2

 

​

 

Dividing by 30xose(sec(45))  

2

(sin(60))  

2

 undoes the multiplication by 30xose(sec(45))  

2

(sin(60))  

2

.

c  

2

=  

30e(sin(60))  

2

(sec(45))  

2

osx

(tan(60))  

2

−(tan(30))  

2

 

​

 

Divide (tan(60))  

2

−(tan(30))  

2

 by 30xose(sec(45))  

2

(sin(60))  

2

.

c  

2

=  

15e(sin(90)+sin(150))  

2

osx

2(cos(60)−cos(120))(cos(90)+1)

​

 

Take the square root of both sides of the equation.

c=  

15(sin(90)+sin(150))  

e

​

 

−  

osx

30(cos(90)+1)(cos(120)−cos(60))

​

 

​

 

​

 

c=−  

15(sin(90)+sin(150))  

e

​

 

−  

osx

30(cos(90)+1)(cos(120)−cos(60))

​

 

​

 

​

 

Solve for o

o=−  

15esx

2((sin(30)cos(60))  

2

−(sin(60)cos(30))  

2

)×(  

sin(120)cos(30)c

cos(45)

​

)  

2

 

​

,c



=0 and s



=0 and x



=0