(xcosx +sinx) (e raise to x +xraise to 3)
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e ki baba is the answer to the answer to the answer toCorrect option is
D
1Ω
Effective resistance of 2Ω and 2Ω in parallel R
AB
=
2+2
2×2
=1Ω
∴ Equivalent resistance between P and Q, R
PQ
=2∥(1+R
AB
)=2∥2
⟹ R
PQ
=1Ω
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