Question

xcube + 1 divide x square + 2x​

Answer 1

Answer:

$\frac{ {x}^{3} + 1}{ {x}^{2} + 2x } \\ \frac{ {x}^{3} + {1}^{3} }{ {x}^{2} + 2x } \\ \frac{(x + 1)( {x}^{2} - x + 1) }{ x(x + 2)}$

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