Math, asked by ibomchanambam12, 11 months ago

xcube +27 factories by using identities​

Answers

Answered by gayathrivenkatesh143
0

Answer:(X+3) (x^2-3x+9)

Step-by-step explanation:

x^3+27 is also written as x^3+3^3 in the simplest form

Using identity x^3+y^3=(x+y) (x^2-xy+y^²)

Substituting

(x+3) (x^2-3x+3^2)

i.e (X+3) (x^2-3x+9)

Answered by Anonymous
6

HeYa❤️...

Used Identity:

(x + y) {}^{3}  = x {}^{3}  + y {}^{2}  + 3xy(x + y)

Solution:

 = x {}^{3}  + 27 \\  \\  = (x + 3) {}^{3}  \\  \\  = (x) {}^{3}  + (3) {}^{3} + 3(x)(3) (x + 3) \\  \\  = x {}^{3}   + 27 + 9x(x + 3) \\  \\  = x {}^{3}  + 27 + 9x {}^{2}  + 27x

I hOpe It HeLpS Ya!

✌️✌️✌️✌️

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