Question

xcube-2x-5by using bysection method in 5stage​

Answer 1

Answer:

Given

f(x) = x3 - 2 x - 5

f(2) = 23 - 2 (2) - 5 = -1 (negative)

f(3) = 33 - 2 (3) - 5 = 16 (positive)

Let us take a= 2 and b= 3.

The first approximation to root is x1 and is given by

x1 = (a f(a) - b f(b))/(f(b)-f(a))

=(2 f(3)- 3 f(2))/(f(3) - f(2))

=(2 x 16 - 3 (-1))/ (16- (-1))

= (32 + 3)/(16+1) =35/17

= 2.058