Question

xcube-3x=0. Show that there is root of equation between 1 and 2

Answer 1

Answer:

x³-3x=9

take x common

x(x²-3)=0

x=0&x=±root 3

Root 3 v add lue is 1.732

The root 3 is root of equation so it lies b/w 1&2.

Answer 2

Answer:

X³-3x=0

so x(x²-3)=0 & x=0 or

x²-3=0 then x²=3 then x=+_under root 3.

so x€ (1,2). Hope you got it.