Question

xcube+3xsquare-31x+12 ÷ (x-4)​

Answer 1

Answer:

In a car race, car A takes 2 s less than car B and passes the finishing point with a velocity v more than the velocity with which car B passes the point. Both the cars start from rest and travel with constant accelerations of car A = 3 m/s2and car B = 2 m/s2. the value of v is? ans is 4.9 m/s.

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Answer 2

${x}^{2} + 7x - 3$

Step-by-step explanation:

If we put x = 4 in the given expression, value of the expression will be zero.

Thus, by factor theorem, (x - 4) would be a factor of the expression.

Now,

${x}^{3} + 3 {x}^{2} - 31x + 12 \\ = {x}^{3} - 4 {x}^{2} + 7 {x}^{2} - 28x - 3x + 12 \\ = {x}^{2} (x - 4) + 7x(x - 4) </strong><strong>-</strong><strong> 3(x - 4) \\ = (x - 4)( {x}^{2} + 7x </strong><strong>-</strong><strong> 3)$

Hence, after dividing by (x - 4) the quotient will be (x^2 + 7x - 3).