Question

Xcube-3xsqure-9x-5 factorise

Answer 1

Answer:

${x}^{3} - 3x {}^{2} - 9x - 5 = 0$

${x}^{3} + {x}^{2} - 4 {x}^{2} - 4x - 5x - 5 = 0$

${x}^{2} (x + 1) - 4x(x + 1) - 5(x + 1) = 0$

$(x + 1)( {x}^{2} - 4x - 5) = 0$

$(x + 1)( {x}^{2} - 5x + x - 5) = 0$

$(x + 1)(x(x - 5) + 1(x - 5)) = 0$

$(x + 1)(x - 5)(x + 1) = 0$

$(x + 1) {}^{2} (x - 5) = 0$