Question

xcube plus 3x square plus3x minus 7​

Answer 1

Step-by-step explanation:

x^3 + 3x² +3x -7

= x^3 + 3x² + 3x +1 -8

= (x + 1)^3 -(2)^3

Now, use identity

a^3 - b^3 = (a-b) ( a² + ab + b²)

We get, ( x+1 -2) { (x+1)² + 2(x+1) + 2² }

= (x-1) ( x² + 2x + 1 +2x + 2 + 4)

= (x-1) ( x² + 4x + 7)