Question

xcube+ycube+xy (x+y)​

Answer 1

Answer:

The given equation is:

x^3+y^3=(x+y)(x^2-xy+y^2)x

3

+y

3

=(x+y)(x

2

−xy+y

2

)

Taking the right hand side of the above equation, we have

RHS=(x+y)(x^2-xy+y^2)(x+y)(x

2

−xy+y

2

)

RHS=x(x^2-xy+y^2)+y(x^2-xy+y^2)x(x

2

−xy+y

2

)+y(x

2

−xy+y

2

)

RHS=x^3-x^2y+xy^2+x^2y-xy^2+y^3x

3

−x

2

y+xy

2

+x

2

y−xy

2

+y

3

RHS=x^3+y^3x

3

+y

3

RHS=LHS