Math, asked by talhazaid, 11 months ago

xcubeminus xsquareminus two​

Attachments:

Answers

Answered by tahseen619
0

 {m}^{3}  -  {m}^{2}  + 2 = 0 \\  {m}^{3}   +  {m}^{2}   - 2 {m}^{2}  - 2m + 2m + 2 = 0 \\  {m}^{2} (m + 1) - 2m(m + 1) + 2(m + 1) = 0 \\ ( {m}^{2}  - 2m + 2)(m + 1) = 0
Similar questions