Xe do not form XeF3 and XeF5 why?
Answers
Answered by
41
Xe has a complete filled 5p configuration. As a result when it undergoes bonding with an odd number (3 or 5) of F atoms it leaves behind one unpaired electron. This causes the molecule to become unstable. As a result XeF3 and XeF5 do not exist.
Answered by
0
Answer:
- Xe is a nobel gas with fully filled 5p orbitals
- Xe has paired electrons in each of its filled orbitals.
- 2, 4 and 6 half-filled orbitals will form as a result of the promotion of 1, 2, or 3 electrons from the 5p filled orbitals to the 5d unoccupied orbitals.
- Xe can therefore combine with an even number of F-atoms but not an odd number.
- Hence, Xenon is capable of forming compounds containing two or four or six, that is, even number of molecules, for example, XeF4
- But it cannot form with odd number of atoms like XeF3 and XeF5.
#SPJ3
Similar questions