Question

XeF2 has a straight linear structure and not a bend angular structure. give reasons

Answer 1

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Answer 2

$XeF_2$ has a straight linear structure and not a bend angular structure.

Explanation:

• According to the VSEPR theory, the shape of the molecule is determined by the total number of electron pairs (lone pair+bond pair) in the valence shell of the central atom.
• Accordingly, when the given compound is examined it is identified as $XeF_2$.
• It has two $Xe-F$ covalent bonds. Thus it is confirmed as it has 2 pairs of bond electrons and 3 pairs of lone electrons and together has 5 electron pairs.
• Thus the hybridization of the compound is $sp^3d$, due to which the compound has a linear structure.
• For a compound to possesses bend angular structure, it must have $sp^2$ hybridization.

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