Question

XeF6 fluorinates I2 to IF7 and liberates Xenon(g). 210 mmol (milimol) of XeF6 can yield a maximum of _________ mmols of IF7.

a) 420 b) 180 c) 210 d) 245

Answer 1

7XeF6 + 3I2 ➡️ 6IF7 + 7Xe.

So,

7 mol Xef6 ➡️ 6IF7

So, 210 mmole ➡️ x

So, x = 180 mmole.

Option (b).