Chemistry, asked by narendraysn9034, 8 months ago

Xef6 reacts with 2.5m naoh to give

Answers

Answered by sonamedhi
3

Answer:

4XeF6 + 36NaOH → 2Na4XeO6 + Xe + 24NaF + 18H2O

try this chemical equation it will help you

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Answered by shivanijain4931
0

Answer:

When 1 M XeF₆ reacts with 2.5 M NaOH, following reaction takes place:

2XeF₆ + 16NaOH → Na₄XeO₆ + Xe + O₂ + 12NaF + 8H₂O

Thus, when XeF₆ reacts with 2.5 M NaOH, formation of sodium perxenate(Na₄XeO₆) takes place along with other side products.

The given reaction is a type of disproportionation reaction as here XeF₆ is getting oxidised to Na₄XeO₆ and getting reduced to Xe simultaneously.

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