Xef6 reacts with 2.5m naoh to give
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Answered by
3
Answer:
4XeF6 + 36NaOH → 2Na4XeO6 + Xe + 24NaF + 18H2O
try this chemical equation it will help you
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Answered by
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Answer:
When 1 M XeF₆ reacts with 2.5 M NaOH, following reaction takes place:
2XeF₆ + 16NaOH → Na₄XeO₆ + Xe + O₂ + 12NaF + 8H₂O
Thus, when XeF₆ reacts with 2.5 M NaOH, formation of sodium perxenate(Na₄XeO₆) takes place along with other side products.
The given reaction is a type of disproportionation reaction as here XeF₆ is getting oxidised to Na₄XeO₆ and getting reduced to Xe simultaneously.
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