Question

XeO4 + 3F- +6H+ ---> XeO3 + F2 + 3H2O
Identify Oxidizing agent and reducing agent​

Answer 1

Answer:

$XeO3 + 6 H+ + 9 (I)- → 3 (I3)- + Xe + 3 H2O</p><p>This is an oxidation-reduction (redox) reaction:</p><p></p><p>9 I-I - 6 e- → 9 I-1/3</p><p>(oxidation)</p><p></p><p>XeVI + 6 e- → Xe0</p><p>(reduction)</p><p></p><p>I- is a reducing agent, XeO3 is an oxidizing agent.</p><p></p><p>Reactants:</p><p></p><p>XeO3</p><p>Names: Xenon trioxide source: wikidata, accessed: 2019-09-02</p><p>H+</p><p>I-</p><p>Products:</p><p></p><p>I3-</p><p>Xe</p><p>Names: Xenon source: wikidata, accessed: 2019-09-07source: ICSC, accessed: 2019-09-04, Xe source: wikidata, accessed: 2019-09-07, Element 54 source: wikidata, accessed: 2019-09-07</p><p>Appearance: Colourless odourless compressed liquefied gas source: ICSC, accessed: 2019-09-04</p><p>H2O – Water, oxidane source: wikipedia, accessed: 2019-09-27</p><p>Other names: Water (H2O) source: wikipedia, accessed: 2019-09-27, Hydrogen hydroxide (HH or HOH) source: wikipedia, accessed: 2019-09-27, Hydrogen oxide$