Question

(xi) 104^2-4^2 simplify using identities​

Answer 1

104=100+4 so,

The given question is (100+4)² - 4²

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By identity $a^2-b^2=(a+b)(a-b)$, it is equivalent to

(100+4+4) × (100+4-4)

It simplifies into

108 × 100 = 10800

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So the answer is 10800.