Math, asked by nilufakhatunbibi, 3 months ago

xi) a.a – b2 - c2 + 2bc​

Answers

Answered by vikram2256
0

a^2 - b^2 - c^2 +2bc=0

a^2- (b^2 + c^2 - 2bc)=0

a^2 - (b-c)^2=0

a^2 = (b-c)^2

a=b-c

a=b-c

b=-(a+c)

c=a+b

Answered by Anonymous
0

Answer:

Step-by-step explanation:

a² – b²- c²+ 2bc​

=a²-(b²+ c²- 2bc​)

=a²-(b-c)²

=(a+b-c)(a-b+c)

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