xi) a.a – b2 - c2 + 2bc
Answers
Answered by
0
a^2 - b^2 - c^2 +2bc=0
a^2- (b^2 + c^2 - 2bc)=0
a^2 - (b-c)^2=0
a^2 = (b-c)^2
a=b-c
a=b-c
b=-(a+c)
c=a+b
Answered by
0
Answer:
Step-by-step explanation:
a² – b²- c²+ 2bc
=a²-(b²+ c²- 2bc)
=a²-(b-c)²
=(a+b-c)(a-b+c)
Similar questions