Question

(xii) One card is drawn from a well shuffled deck of 52 cards. Then the probability of getting a king or a diamond is- 1 1 3 4 (a) (b) (c) 32 26 26 13 13 (d) Sol. :​

Answer 1

Step-by-step explanation:

The probability of getting a king =4÷52=1÷13

The probability of getting a diamond=10÷52=5÷26

Answer 2

Answer:

Probabilty of getting a KING OR a DIAMOND is $\frac{4}{13}$.

Step-by-step explanation:

Probability of getting a king OR a diamond is equal to

$\frac{total no .of favourable card}{total cards}$

There are 13 diamond cards (including king) + 4 KING cards in a set of 52 cards.

The DIAMOND KING IS REPEATED  TWICE,

Hence,we have to subtract the repetition of the card in order to get correct answer.

NOW, the condition is for 'OR' hence we have to 'ADD'  both the cases and subtract the repetition (by 1).

∴No.of favourable cards = 13+4-1=16

Hence, probabilty of getting a KING OR a DIAMOND=$\frac{16}{52}$=$\frac{4}{13}$.