Math, asked by diwandhbakshi, 9 months ago

(xii) sin2 60° + cos2 (3x -9°) = 1

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Answered by tennetiraj86

Answer:

answer for the given problem is given

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Answered by MysteriousAryan

Step-by-step explanation:

$sin {}^{2} 60 + cos {}^{2} (3x - 9) = 1 \\ as \: we \: know \: sin60 = \frac{ \sqrt{3} }{2} \\ and \: cos(3x - 9) = 1 - \frac{3}{2} \\ \\ 3x - 9 = 60 \\ x = 23$

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(xii) sin2 60° + cos2 (3x -9°) = 1​

Answers

(xii) sin2 60° + cos2 (3x -9°) = 1