Question

xii) The denominator of a common fraction exceeds
the numerator by 7. If 3 is deducted from
the numerator as well as the denominator,
2/3
the fraction is obtained. Find the original

common fraction.​

Answer 1

Step-by-step explanation:

Let the numerator of the number be x

Therefore denominator =x+7

when 3 is deducted from numerator it becomes x-3

and when 3 is deducted from denominator it becomes x+7-3=x+4

ATP,

x-3/x+4=2/3

or, 3x-9=2x+8

or, 3x-2x=8+9

or, x=17

And) Therefore numerator =x-3=17-3=14

and denominator =x+4=17+4=21

Hope it helps....

Answer 2

Step-by-step explanation:

Let the numerator of the number be x

Therefore denominator =x+7

when 3 is deducted from numerator it becomes x-3

and when 3 is deducted from denominator it becomes x+7-3=x+4

ATP,

x-3/x+4=2/3

or, 3x-9=2x+8

or, 3x-2x=8+9

or, x=17

And) Therefore numerator =x-3=17-3=14

and denominator =x+4=17+4=21