xis of a ring
at rest is
5.
A particle of mass 'm' moves on the axis of a
of radius 'R' and mass M. If particle at ren
released from 'P then its kinetic energy at cent
c will be
(
Rm
Ć BR P
GMm
(1)
GMm
R
(2) ZR
2GMm
(3)
GMm
3R
B
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★ Applying law of conservation of energy
P.E (f) + K.E(f) = P.E (i) + K.E (i)
initial k.e = O , as particle is at rest
=> -GMm/R + K.E(f) = -GMm/√(R²+x²) + 0
( x= √3R)
=> -GMm/R + K.E (f) = -GMm/2R
=> K.E(f) = GMm/2R
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