Physics, asked by Rocky904350, 10 months ago

xis of a ring
at rest is
5.
A particle of mass 'm' moves on the axis of a
of radius 'R' and mass M. If particle at ren
released from 'P then its kinetic energy at cent
c will be
(
Rm
Ć BR P
GMm
(1)
GMm
R
(2) ZR
2GMm
(3)
GMm
3R
B​

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Answers

Answered by itzIntrovert
41

\huge\bigstar\underline\pink{Answer}

★ Applying law of conservation of energy

P.E (f) + K.E(f) = P.E (i) + K.E (i)

initial k.e = O , as particle is at rest

=> -GMm/R + K.E(f) = -GMm/√(R²+x²) + 0

( x= 3R)

=> -GMm/R + K.E (f) = -GMm/2R

=> K.E(f) = GMm/2R

\boxed{option\:2\:is\: correct}

Happy to help!

☺️

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