(xiv) If the magnitude
magnitude of sum of two vectors is
equal to the magnitude of difference of two
vectors, the angle between these vectors is
(a) o°(b) 10° (6 45° (d) 180°
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Answer:
sum of two vectors
= √a^2+ b^2+2ab×cos theta
difference of two vectors
= √a^2+ b^2-2ab× cos theta
according to the question,
√a^2 + b^2 + 2ab×cos theta
=√a^2 + b^2 - 2ab×cos theta
squaring on both sides,
a^2 + b^2 + 2ab×cos theta
= a^2 + b^2 - 2ab×cos theta
that is,
4ab×cos theta = 0
4ab depends on a and b and can never be 0
so, here, cos theta should be 0
cos theta = 0
theta = 90°
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