Question

xka power 3 - 3x ka square - 9x - 5​

Answer 1

Step-by-step explanation:

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Answer 2

${x}^{3} - 3 {x}^{2} - 9x - 5 \\ \\ = >{x}^{3} + ( {x}^{2}- 4 {x}^{2} ) + ( - 4x - 5x) - 5 \\ \\ = > {x}^{3} + {x}^{2}- 4 {x}^{2} - 4x - 5x - 5 \\ \\ = > {x}^{2} (x + 1) - 4x(x + 1) - 5(x + 1) \\ \\ = > (x + 1)( {x}^{2} - 4x - 5) \\ \\ = > (x + 1)( {x}^{2} - 5x + x - 5) \\ \\ = > (x + 1)[x(x - 5) + 1(x - 5)] \\ \\ = > (x + 1)(x - 5)(x + 1) \\ \\ = > {(x + 1)}^{2} (x - 5)$