Math, asked by ANKURKRISHNA, 10 months ago

xm+n xxn+l xxl+m
(xom xxn xx)2​

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Answers

Answered by knjroopa
15

Step-by-step explanation:

  • Now the equation will be x^3 – 3x^2 – 3x – 5
  • Given to solve x^m + n x x^n + l x x^l + m / ( x^m x x^n x x^l )^2
  • Using the formula for exponents a^m + a^n = a^m + n
  • Therefore x^m + n + n + l + l + m / x^2 (m + n + l)
  • Now x^2m + 2n + 2l / x^2m + 2n + 2l
  •         = 1  (proved)

Reference link will be

https://brainly.in/question/3324986

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