Question

XP & XQ are two tangents to a circle with centre O from a point X outside the circle .ARB is another tangent to the circle @ point of contact R . Prove that : XA + AR = XB + BR Plz ans . this ques. quickly ;)

Answer 1

there is an external point X from where two tangents, XP and XQ, are drawn to the circle. 
XP = XQ (The lengths of the tangents drawn from an external point to the circle are equal.)
Similarly,
AP = AR
BQ = BR
XP = XA + AP --------- (1)
XQ = XB + BQ --------- (2)
By substituting AP = AR in equation (1) and BQ = BR in equation (2), we get
XP = XA + AR
XQ = XB + BR
Since the tangents XP and XQ are equal, we get
XA + AR = XB + BR.

Answer 2

Answer:

Step-by-step explanation:

To prove :

XA+AR=XB+BR

Proof:

XP=XQ

AP=AR

BQ=BR

=>XP+AP=XB+BQ

XA+AP=XB+BR

Hence proved