Question

Xp - x + 1 is irreducible over lf p only when n = 1 or n = p = 2. [note that if a is a root, then so is a + a for any a e lf p. show that this implies lf p (a) contains lf p and that [jf p(a) : lf p ] = p

Answer 1

$17xy - 14xy$