Math, asked by jino444, 7 months ago

xpand (3x+4y) 3 using suitable identity

Answers

Answered by bhavanaRS

1

Answer:

(a+b)³=a³+3a²b+3ab²+b³

(3x+4y)³=9x³+64x³+108x²y+144xy²

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Step-by-step explanation:

Answered by vaishnavisrinivas240

1

Answer:

multiply 3 with (3x+4y)

= 3(3x)+3(4y)

= 9x + 12y

so

(3x +4y)=9x +12y

Step-by-step explanation:

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