xpower2/3+xpower1/3-2=0
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Given equation is x^⅔ + x^⅓ - 2 = 0
Putting x 1/3 = y,
The given equation becomes
y² + y – 2 = 0
⇒ y² + 2y – y – 2 = 0
⇒ y(y+ 2) – 1(y + 2) = 0
⇒ (y + 2) (y – 1) = 0
⇒ y + 2 = 0 or y – 1 = 0
⇒ y = - 2 or y = 1
But x^1/3 = y
∴ x^1/3 = - 2 or x^1/3 = 1
⇒ x = (- 2)³ or x = (1)³
⇒ x = - 8 or x = 1
Hence, roots are -8, 1.
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