Xsin^3a+ycos^3a=sina*cosa and xsina-ycosa=0 then x^2+y^2=?
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Given xSinA – yCosA = 0
⇒ x.SinA = y CosA ........(1)
Consider
{From eq 1}
xSinA = SinACosA
x = CosA ......(2)
Substitute this value in the eq (1)
We get y = SinA
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