Question

Xsin(a+y)+sina cos(a+y)=0 prove that dy/dx=sin^2(a+y)/sina

Answer 1

Answer:

Step-by-step explanation:

Xsin(a+y)+sinacos(a+y)=0

Xsin(a+y)=-sina.cos(a+y)

Sin(a+y)/cos(a+y)=-sina/x

tan(a+y)=-sina/x

Sec^2(a+y)dy/dx=sina/x^2

dy/dx=sina.sin^2(a+y).cos^2(a+y)/sin^2a.cos^(a+y) since x=-sina.cis(a+y)/sin(a+y)

dy/dx=sin^2(a+y)/sina

Proved