xsin230*cos260/4cos245 =3sin245+2cos230/sin290-4cos45 determine
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If
4cos
2
60
o
xsin
2
45
o
×cos
2
30
o
=
sin
2
90
o
+2cos
2
45
o
3sin
2
45
o
×2cos
2
30
o
, then what is the value of x?
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Solution
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Correct option is C)
Given,
4cos
2
60
xsin
2
45×cos
2
30
=
sin
2
90+2cos
2
45
3sin
2
45×2cos
2
30
4(
2
1
)
2
x(
2
1
)
2
×(
2
3
)
2
=
(1)
2
+2(
2
1
)
2
3(
2
1
)
2
×2(
2
3
)
2
1
8
3x
=
2
4
9
8
3x
=
8
9
3x=9
∴x=3
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