xsq +3x -10 find the zeroes
Answers
Answered by
1
Hello,
Zeroes can be found by finding the factorization.
we can see that the polynomial is quadratic so we can do middle term splitting.
P(x) =x²+3x - 10
inheritance fitting we get p (x) equals to :-
P(x) = x²+5x - 2x - 10
P(x) = x(x+5) - 2(x+5)
P(x) = (x+5) (x-2)
From factor theorem, we can say that
The Zeroes are -
(x+5)=0
So, x = (-5)
(x-2) = 0
So, x = 2
the zeros are (2) and (- 5)
Hope this will be helping you ✌️
Zeroes can be found by finding the factorization.
we can see that the polynomial is quadratic so we can do middle term splitting.
P(x) =x²+3x - 10
inheritance fitting we get p (x) equals to :-
P(x) = x²+5x - 2x - 10
P(x) = x(x+5) - 2(x+5)
P(x) = (x+5) (x-2)
From factor theorem, we can say that
The Zeroes are -
(x+5)=0
So, x = (-5)
(x-2) = 0
So, x = 2
the zeros are (2) and (- 5)
Hope this will be helping you ✌️
Answered by
0
Hey dear !!!
__________________________
==> In the example
p(x) = x² + 3x - 10
We have to find the zeroes of this quadratic polynomial .
We know that by splitting the middle term we can find the zeroes of any polynomial . So lets do it !!!
=> x² +3x - 10
=> x² + 5x - 2x - 10
=> x(x + 5) -2(x + 5)
=> ( x + 5) (x - 2)
If x + 5 = 0
∴ x = -5 is the first zero
If x - 2 = 0
∴ x = 2 is the second zero
Therefore, -5 and 2 are the zeroes of the given quadratic polynomial .
Thanks !!!!
[ Be Brainly ]
__________________________
==> In the example
p(x) = x² + 3x - 10
We have to find the zeroes of this quadratic polynomial .
We know that by splitting the middle term we can find the zeroes of any polynomial . So lets do it !!!
=> x² +3x - 10
=> x² + 5x - 2x - 10
=> x(x + 5) -2(x + 5)
=> ( x + 5) (x - 2)
If x + 5 = 0
∴ x = -5 is the first zero
If x - 2 = 0
∴ x = 2 is the second zero
Therefore, -5 and 2 are the zeroes of the given quadratic polynomial .
Thanks !!!!
[ Be Brainly ]
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