(xsq-6xsq+9x+7)is divided by(x-1)
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Question:
x³-6x²+9x+7 /x-1
Step-by-step explanation:
We get,
Q = X²-5X+4 & R = 7
FACTORIES THE QUOTIENT X²-5X+4
Then,
We get the zeros of the polynomial X²-5X+4
X²-5X+4
X²-4X-X +4
X(X-4) + 1 ( X-4)
(X-4) ( X+1)
X-4 = 0. X+1 = 0
X = 4. X = -1.
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