xsqare-2x=(-2)(3-x)
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Step-by-step explanation:
x^2-2x= (-2)(3-x)
x^2-2x= (-2)3 -x(-2)
x^2-2x= -6+2x
x^2-2x-2x+6=0
x^2-4x+6=0
a=1,b=-4,c=6
Using quadratic formula;
x=+4 +underoot 16-24/2
=4 +under root 8/2
=4+2 underoot2/2 , 4-2underoot2/2
=2(2+1underoot2)/2 , 2(2-1underoot2)/2
x=2+underoot2 , 2-underoot2
[AS 2 IN DENOMINATOR CUTS 2 IN NUMERATOR]
Therefore; value of x= 2+underoot2 or 2- underoot2
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