Math, asked by abdulrehman79, 1 year ago

xsqare-2x=(-2)(3-x)​

Answers

Answered by WWWSINGHDEVILAL1499
0

Answer:

Step-by-step explanation:

x^2-2x= (-2)(3-x)

x^2-2x= (-2)3 -x(-2)

x^2-2x= -6+2x

x^2-2x-2x+6=0

x^2-4x+6=0

a=1,b=-4,c=6

Using quadratic formula;

x=+4 +underoot 16-24/2

 =4 +under root 8/2

 =4+2 underoot2/2      ,    4-2underoot2/2

 =2(2+1underoot2)/2    ,    2(2-1underoot2)/2

 x=2+underoot2           ,    2-underoot2

[AS 2 IN DENOMINATOR CUTS 2 IN NUMERATOR]

Therefore; value of x= 2+underoot2 or 2- underoot2

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