Math, asked by STALINMALIK, 1 year ago

xsquare×1/xsquare=11 find xcube-1/xcube

Answers

Answered by AlexThundrous
0

 {x}^{2}  +  \frac{1}{ {x}^{2} }  = 11
subtracting 2 on both sides
 {x}^{2}  +  \frac{1}{ {x}^{2} }  - 2 = 9
 {x}^{2}   +  \frac{1}{ {x}^{2} }  - 2 \times x \times  \frac{1}{x}  = 9
of x = a and 1/x =b then
 {a}^{2}  +  {b}^{2}   - 2ab = {(a  -  b)}^{2}
{( {x} -  \frac{1}{x} )}^{2}  = 9 \\ x -  \frac{1}{x} = 3
{(x -  \frac{1}{x})}^{3}  =  27
 {x}^{3} -  {\frac{1}{x} }^{3}  - 3 \times x \times  \frac{1}{x} (x -  \frac{1}{x} ) = 27
 {x}^{3}  -  { (\frac{1}{x}) }^{3} - 3(3) = 27
 {x}^{3}  -  {(\frac{1}{x})}^{3} = 36
Hence the answer is 36.
Hope it helps and if possible then please mark it as the brainliest answer.

AlexThundrous: please mark it as the brainliest answer
STALINMALIK: minus 2 y u have done
AlexThundrous: To find the square valie
AlexThundrous: valie
AlexThundrous: value
AlexThundrous: So that I could convert it to a perfect square
STALINMALIK: which class do you read
AlexThundrous: I m in 9th class
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