xsquare-3x+2. x=2 find the answer
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2^2-3(2)+2=4-6+2 = 0
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● Factorisation ●
x² - 3x + 2 = 0
=> x² - 2x - x + 2 = 0
=> x(x - 2) - 1(x - 2) = 0
=> (x - 1)(x - 2) = 0
So,
x - 1 = 0
=> x = 1
when, x = 2,
x² - 3x + 2
= (2)² - 3×2 + 2
= 4 - 6 + 2
= 0
OR
x - 2 = 0
=> x = 2
x² - 3x + 2 = 0
=> x² - 2x - x + 2 = 0
=> x(x - 2) - 1(x - 2) = 0
=> (x - 1)(x - 2) = 0
So,
x - 1 = 0
=> x = 1
when, x = 2,
x² - 3x + 2
= (2)² - 3×2 + 2
= 4 - 6 + 2
= 0
OR
x - 2 = 0
=> x = 2
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