(xsquare-3x)square+3(xsquare-3x)+2=0 how to slove this problem
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(x²-3x)²+3(x²-3x)+2=0
Taking common,
(x²-3x)(x²-3x+2)=0
Either,x²-3x=0
Or x²-3x+2=0
So simplify it
when
x²-3x=0
x(x-3)=0
x-3=0
x=3
When
x²-3x+2=0
x²-2x-x+2=0
x(x-2)-1(x-2)=0
(x-1)(x-2)=0
So
Either x=1 or x=2
So possible answers of x are 1,2,3
Taking common,
(x²-3x)(x²-3x+2)=0
Either,x²-3x=0
Or x²-3x+2=0
So simplify it
when
x²-3x=0
x(x-3)=0
x-3=0
x=3
When
x²-3x+2=0
x²-2x-x+2=0
x(x-2)-1(x-2)=0
(x-1)(x-2)=0
So
Either x=1 or x=2
So possible answers of x are 1,2,3
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