Question

xsquare +4x+1=0 discriminate​

Answer 1

Answer:

x²+4x+1=0

a=1

b=4

c=1

D = discriminant = b²-4ac

D=(4)²-4(1)(1)

=16-4

D=12

Answer 2

Given:

• A quadratic equation x²+4x+1=0

To Find:

• The value of discriminant.

Answer:

For a quadratic equation of standard form ax²+bx + c , Discriminant is known as b²-4ac .

The discriminant tells the nature of root .

Now , with respect to standard form ,

• a = 1
• b = 4
• c = 1

Hence value of discriminant ,

$\sf{\implies Discriminant = b^2-4ac}$

$\sf{\implies Discriminant = (4)^2 -4\times 1\times1}$

$\sf{\implies Discriminant =16-4}$

$\bf{\implies Discriminant =12}$

Hence the discriminant is 12 .

Note:

• When D>0 ,roots are real.
• When D=0 ,roots are equal.
• When D<0 ,roots are complex conjugates.