Question

Xsquare + 8x - 48 = 0
solve.... using completing square method ​

Answer 1

hope this answer will be helpful

Answer 2

Step-by-step explanation:

Solving x2-8x-48 = 0 by Completing The Square .

Add 48 to both side of the equation :

x2-8x = 48

Now the clever bit: Take the coefficient of x , which is 8 , divide by two, giving 4 , and finally square it giving 16

Add 16 to both sides of the equation :

On the right hand side we have :

48 + 16 or, (48/1)+(16/1)

The common denominator of the two fractions is 1 Adding (48/1)+(16/1) gives 64/1

So adding to both sides we finally get :

x2-8x+16 = 64

Adding 16 has completed the left hand side into a perfect square :

x2-8x+16 =

(x-4) • (x-4) =

(x-4)2

Things which are equal to the same thing are also equal to one another. Since

x2-8x+16 = 64 and

x2-8x+16 = (x-4)2

then, according to the law of transitivity,

(x-4)2 = 64

We'll refer to this Equation as Eq. #3.2.1

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of

(x-4)2 is

(x-4)2/2 =

(x-4)1 =

x-4

Now, applying the Square Root Principle to Eq. #3.2.1 we get:

x-4 = √ 64

Add 4 to both sides to obtain:

x = 4 + √ 64

Since a square root has two values, one positive and the other negative

x2 - 8x - 48 = 0

has two solutions:

x = 4 + √ 64

or

x = 4 - √ 64